If 17.32v are applied across a resistance of 50 ohms, how much power is expanded in the resistor?

To determine the power dissipated in a resistor when a certain voltage is applied, you can use the formula for electrical power, which is given by:

[ P = \frac{V^2}{R} ]

Where:

• ( P ) is the power in watts,

• ( V ) is the voltage across the resistor in volts,

• ( R ) is the resistance in ohms.

In this case, the voltage ( V ) is 17.32 volts and the resistance ( R ) is 50 ohms. Plugging these values into the formula gives:

[ P = \frac{(17.32)^2}{50} ]

Calculating ( (17.32)^2 ):

[ (17.32)^2 = 299.1824 ]

Now divide this by the resistance:

[ P = \frac{299.1824}{50} = 5.983648 ]

Rounding this to a suitable number of significant figures, the power dissipated in the resistor is approximately 6.0 watts.

Thus, the choice that accurately reflects this calculation is 6.0 watts. This result is consistent with the application of the power formula in relation to voltage and